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-6x^2-3x+25=0
a = -6; b = -3; c = +25;
Δ = b2-4ac
Δ = -32-4·(-6)·25
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{609}}{2*-6}=\frac{3-\sqrt{609}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{609}}{2*-6}=\frac{3+\sqrt{609}}{-12} $
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